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L(x)=2xL\left(x\right)=2xL(x)=2x
L(x)=1+x−12ln(2)L\left(x\right)=1+\frac{x-1}{2\ln\left(2\right)}L(x)=1+2ln(2)x−1
L(x)=1+x+12ln(2)L\left(x\right)=1+\frac{x+1}{2\ln\left(2\right)}L(x)=1+2ln(2)x+1
L(x)=1+x+1ln(2)L\left(x\right)=1+\frac{x+1}{\ln\left(2\right)}L(x)=1+ln(2)x+1
L(x)=3L\left(x\right)=3L(x)=3
L(x)=x+1ln(4)L\left(x\right)=\frac{x+1}{\ln\left(4\right)}L(x)=ln(4)x+1
L(x)=x−1ln(4)L\left(x\right)=\frac{x-1}{\ln\left(4\right)}L(x)=ln(4)x−1
L(x)=xln(4)L\left(x\right)=\frac{x}{\ln\left(4\right)}L(x)=ln(4)x
L(x)=log3(−2)−x+12ln(3)L\left(x\right)=\log_3\left(-2\right)-\frac{x+1}{2\ln\left(3\right)}L(x)=log3(−2)−2ln(3)x+1
L(x)=log3(−2)−x2ln(3)L\left(x\right)=\log_3\left(-2\right)-\frac{x}{2\ln\left(3\right)}L(x)=log3(−2)−2ln(3)x
L(x)=log3(−2)−x2ln(1)L\left(x\right)=\log_3\left(-2\right)-\frac{x}{2\ln\left(1\right)}L(x)=log3(−2)−2ln(1)x
L(x)=x+1ln(5)L\left(x\right)=\frac{x+1}{\ln\left(5\right)}L(x)=ln(5)x+1
L(x)=x−1ln(5)L\left(x\right)=\frac{x-1}{\ln\left(5\right)}L(x)=ln(5)x−1
L(x)=xln(5)L\left(x\right)=\frac{x}{\ln\left(5\right)}L(x)=ln(5)x
L(x)=log2(−1)−xln(2)L\left(x\right)=\log_2\left(-1\right)-\frac{x}{\ln\left(2\right)}L(x)=log2(−1)−ln(2)x
L(x)=logL\left(x\right)=\logL(x)=log
L(x)=log2L\left(x\right)=\log2L(x)=log2
L(x)=0L\left(x\right)=0L(x)=0
L(x)=xln(2)L\left(x\right)=\frac{x}{\ln\left(2\right)}L(x)=ln(2)x
L(x)=1ln(2)L\left(x\right)=\frac{1}{\ln\left(2\right)}L(x)=ln(2)1
L(x)=xln(x)L\left(x\right)=\frac{x}{\ln\left(x\right)}L(x)=ln(x)x
إنتهى الإختبار.