1 / 10
00
حدد الرسم البياني للقطع الناقص
x29+(y−3)24=1\frac{x^2}{9}+\frac{\left(y-3\right)^2}{4}=19x2+4(y−3)2=1
باستخدام الإزاحة
(x−2)24+(y−3)225=1\frac{\left(x-2\right)^2}{4}+\frac{\left(y-3\right)^2}{25}=14(x−2)2+25(y−3)2=1
x24+(y−5)216=1\frac{x^2}{4}+\frac{\left(y-5\right)^2}{16}=14x2+16(y−5)2=1
x29+(y−3)216=1\frac{x^2}{9}+\frac{\left(y-3\right)^2}{16}=19x2+16(y−3)2=1
(x+2)225+y24=1\frac{\left(x+2\right)^2}{25}+\frac{y^2}{4}=125(x+2)2+4y2=1
(x−4)216+y24=1\frac{\left(x-4\right)^2}{16}+\frac{y^2}{4}=116(x−4)2+4y2=1
(x−1)29+y24=1\frac{\left(x-1\right)^2}{9}+\frac{y^2}{4}=19(x−1)2+4y2=1
باستخدام الازاحة
(x−1)236+(y+1)225=1\frac{\left(x-1\right)^2}{36}+\frac{\left(y+1\right)^2}{25}=136(x−1)2+25(y+1)2=1
x225+(y+2)216=1\frac{x^2}{25}+\frac{\left(y+2\right)^2}{16}=125x2+16(y+2)2=1
(x+2)216+(y+2)225=1\frac{\left(x+2\right)^2}{16}+\frac{\left(y+2\right)^2}{25}=116(x+2)2+25(y+2)2=1
إنتهى الإختبار.