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حدد دالة القاطع من مجموعة الأزواج المرتبة المعطاة:
{(0°,4), (30°,83\frac{8}{\sqrt{3}}38), (45°, 424\sqrt{2}42), (60°,8), (90°,∞\infty∞)}.
y=2sec(x)y=2\sec\left(x\right)y=2sec(x)
y=4sec(x)y=4\sec\left(x\right)y=4sec(x)
y=csc(3x)y=\csc\left(3x\right)y=csc(3x)
{(0°,1), (15°,23\frac{2}{\sqrt{3}}32), (22.5°, 2\sqrt{2}2), (30°,2), (45°,∞\infty∞)}.
y=sec(x)y=\sec\left(x\right)y=sec(x)
y=sec(2x)y=\sec\left(2x\right)y=sec(2x)
y=sec(x+30°)y=\sec\left(x+30°\right)y=sec(x+30°)
{(0°,2), (15°,43\frac{4}{\sqrt{3}}34), (22.5°, 222\sqrt{2}22), (30°,4), (45°,∞\infty∞)}.
y=2sec(2x)y=2\sec\left(2x\right)y=2sec(2x)
y=−csc(x−30°)y=-\csc\left(x-30°\right)y=−csc(x−30°)
{(30°, 1), (60°, 23\frac{2}{\sqrt{3}}32), (75°, 2\sqrt{2}2), (90°,2), (120°, ∞\infty∞)}.
y=sec(x−30°)y=\sec\left(x-30°\right)y=sec(x−30°)
{(0°,1), (90°,23\frac{2}{\sqrt{3}}32), (135°,2\sqrt{2}2), (180°,2), (270°,∞\infty∞)}.
y=sec(x3)y=\sec\left(\frac{x}{3}\right)y=sec(3x)
{(0°,1), (30°, 23\frac{2}{\sqrt{3}}32), (45°, 2\sqrt{2}2), (60°,2), (90°,∞\infty∞)}.
y=sec(−x)y=\sec\left(-x\right)y=sec(−x)
{ (-30°,1), (0°, 23\frac{2}{\sqrt{3}}32), (15°, 2\sqrt{2}2), (30°, 2), (60°, ∞\infty∞) }.
y=sec(−2x)y=\sec\left(-2x\right)y=sec(−2x)
{(0°,1), (60°,23\frac{2}{\sqrt{3}}32), (90°, 2\sqrt{2}2), (120°,2), (180°, ∞\infty∞)}.
y=sec(x2)y=\sec\left(\frac{x}{2}\right)y=sec(2x)
{(-30°, -1), (0°,−23\frac{-2}{\sqrt{3}}3−2), (15°,−2-\sqrt{2}−2), (30°, -2), (60°,∞\infty∞)}.
y=−sec(x+30°)y=-\sec\left(x+30°\right)y=−sec(x+30°)
إنتهى الإختبار.