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حدد دالة القاطع من الرسم البياني:
y=sec(x)y=\sec\left(x\right)y=sec(x)
y=sec(3+x)y=\sec\left(3+x\right)y=sec(3+x)
y=4sec(x+2)y=4\sec\left(x+2\right)y=4sec(x+2)
y=sec(x+23)y=\sec\left(\frac{x+2}{3}\right)y=sec(3x+2)
y=sec(2x)y=\sec\left(2x\right)y=sec(2x)
y=sec(3x)y=\sec\left(3x\right)y=sec(3x)
y=csc(3x)y=\csc\left(3x\right)y=csc(3x)
y=4sec(x)y=4\sec\left(x\right)y=4sec(x)
y=sec(x+7)y=\sec\left(x+7\right)y=sec(x+7)
y=tan(x)y=\tan\left(x\right)y=tan(x)
y=3sec(x−1)y=3\sec\left(x-1\right)y=3sec(x−1)
y=sec(x3)y=\sec\left(\frac{x}{3}\right)y=sec(3x)
y=4tan(x)y=4\tan\left(x\right)y=4tan(x)
y=sec(x2)y=\sec\left(\frac{x}{2}\right)y=sec(2x)
y=sec(x−5)y=\sec\left(x-5\right)y=sec(x−5)
إنتهى الإختبار.