$4x-4x$

$2\sin3x\cos3x$

$\frac{\left(1-3x\right)}{\left(1+3x\right)}$

4x−4x

$2\sin3x\cos3x$

$\frac{2\tan5x}{1+5x}$

$4x-4x$

$2\sin3x\cos3x$

$\frac{2\tan6x}{1+6x}$

$2x-2x$

$2\sin3x\cos3x$

$\frac{\left(1-3x\right)}{\left(1+3x\right)}$

$4x-4x$

$\tan x$

$\frac{2\tan5x}{1+5x}$

$\frac{2\tan4x}{1+\tan^24x}$

$2\sin3x\cos3x$

$\frac{\left(1-3x\right)}{\left(1+3x\right)}$

$\frac{2\tan4x}{1+\tan^24x^{ }}$

$2\sin x\cos x$

$\frac{\left(1-3x\right)}{\left(1+3x\right)}$

$\frac{2\tan4x}{1+\tan^24x}$

$\frac{\tan4x}{4x}$

$\frac{\left(1-3x\right)}{\left(1+3x\right)}$

$4x-4x$

$2\sin3x\cos3x$

$\tan\tan\left(\frac{x}{\left(2\right)}\right)$

$\sec2x$

$\sin3x$

$\frac{2\tan5x}{1+5x}$