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Find the equation of line perpendicular to y=−112x+2y=-\frac{1}{12}x+2y=−121x+2
y=12x+7y=12x+7y=12x+7
y=10x+2y=10x+2y=10x+2
y=−112x+7y=-\frac{1}{12}x+7y=−121x+7
Find the equation of line perpendicular to y=x+1y=x+1y=x+1
y=5x+8y=5x+8y=5x+8
y=−x+8y=-x+8y=−x+8
y=2x+1y=2x+1y=2x+1
Find the equation of line perpendicular to y=2x−10y=2x-10y=2x−10
y=2x+17y=2x+17y=2x+17
y=−12x+6y=-\frac{1}{2}x+6y=−21x+6
Find the equation of line perpendicular to y=5x+1y=5x+1y=5x+1
y=5x+24y=5x+24y=5x+24
y=−15x+11y=-\frac{1}{5}x+11y=−51x+11
Find the equation of line perpendicular to y=7x−9y=7x-9y=7x−9
y=x+7y=x+7y=x+7
y=7x+11y=7x+11y=7x+11
y=−17x−11y=-\frac{1}{7}x-11y=−71x−11
Find the equation of line perpendicular to y=57x+15y=\frac{5}{7}x+15y=75x+15
y=−75x+8y=-\frac{7}{5}x+8y=−57x+8
y=2x+5y=2x+5y=2x+5
y=57x+9y=\frac{5}{7}x+9y=75x+9
Complete:
If two lines are perpendicular, then their slopes are____.
m1=m2m_1=m_2m1=m2
m1m2=−1m_1m_2=-1m1m2=−1
m1+m2=1m_1+m_2=1m1+m2=1
Find the equation of line perpendicular to y=6x−5y=6x-5y=6x−5
y=2x+7y=2x+7y=2x+7
y=6x+2y=6x+2y=6x+2
y=−16x+2y=-\frac{1}{6}x+2y=−61x+2
Find the equation of line perpendicular to y=23x+1y=\frac{2}{3}x+1y=32x+1
y=−32x+8y=-\frac{3}{2}x+8y=−23x+8
y=23x+2y=\frac{2}{3}x+2y=32x+2
Find the equation of line perpendicular to y=2x+3y=2x+3y=2x+3
y=3x+2y=3x+2y=3x+2
y=−12x+7y=-\frac{1}{2}x+7y=−21x+7
It is done.