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Which of the following is a cosine function?
g(x)=sinxg(x)=\sin xg(x)=sinx
h(x)=cosxh(x)=\cos xh(x)=cosx
f(x)=−2cosxf(x)=-2\cos xf(x)=−2cosx
f(x)=x+1cosxf(x)=\frac{x+1}{\cos x}f(x)=cosxx+1
Which refers to the general form of a cosine function?
g(x)=ax3+bx2+cx+dg(x)=ax^3+bx^2+cx+dg(x)=ax3+bx2+cx+d
f(x)=ax2+cf(x)=ax^2+cf(x)=ax2+c
h(x)=aCosx+bh(x)=aCosx+bh(x)=aCosx+b
f(x)=2cosx+2f(x)=2\cos x+2f(x)=2cosx+2
f(x)=cosx+2f(x)=\cos^{x+2}f(x)=cosx+2
g(x)=Cosxg(x)=Cosxg(x)=Cosx
h(x)=tanxh(x)=\tan xh(x)=tanx
f(x)=2cosxf(x)=2\cos xf(x)=2cosx
f(x)=xcosf(x)=x^{\cos}f(x)=xcos
Is the sentence true or false?
f(x)=Cos4xf(x)=Cos4xf(x)=Cos4x is a cosine function.
True
False
f(x)=−cosxf(x)=-\cos xf(x)=−cosx
f(x)=x+1f(x)=x+1f(x)=x+1
f(x)=cos(x−1)f(x)=\cos(x-1)f(x)=cos(x−1)
h(x)=Sinx+4h(x)=Sinx+4h(x)=Sinx+4
f(x)=cos2xf(x)=\cos2xf(x)=cos2x
f(x)=2cosf(x)=2^{\cos}f(x)=2cos
It is done.