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Which of the following is a cosine function?
f(x)=−cosxf(x)=-\cos xf(x)=−cosx
f(x)=x+1f(x)=x+1f(x)=x+1
f(x)=cos(x−1)f(x)=\cos(x-1)f(x)=cos(x−1)
h(x)=Sinx+4h(x)=Sinx+4h(x)=Sinx+4
f(x)=cos2xf(x)=\cos2xf(x)=cos2x
f(x)=2cosf(x)=2^{\cos}f(x)=2cos
f(x)=2cos2xf(x)=2\cos2xf(x)=2cos2x
f(x)=2cos+1f(x)=2^{\cos}+1f(x)=2cos+1
f(x)=sin2xf(x)=\sin2xf(x)=sin2x
h(x)=cos(x2+4)h(x)=\cos(x^2+4)h(x)=cos(x2+4)
f(x)=cosxf(x)=\cos xf(x)=cosx
f(x)=sinxf(x)=\sin xf(x)=sinx
f(x)=2cosxf(x)=2\cos xf(x)=2cosx
f(x)=xcosf(x)=x^{\cos}f(x)=xcos
Is the sentence true or False?
f(x)=Sinxf(x)=Sinxf(x)=Sinx is a cosine function.
True
False
f(x)=cosx+2f(x)=\cos x+2f(x)=cosx+2
f(x)=cosx+2f(x)=\cos^{x+2}f(x)=cosx+2
f(x)=2x3−1f(x)=2x^3-1f(x)=2x3−1
h(x)=Cos3xh(x)=Cos3xh(x)=Cos3x
It is done.