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L(x)=−xL\left(x\right)=-xL(x)=−x
L(x)=xL\left(x\right)=xL(x)=x
L(x)=2xL\left(x\right)=2xL(x)=2x
Determine the linear approximation of f(x)=x3+6f\left(x\right)=x^3+6f(x)=x3+6 at a=0.
L(x)=6L\left(x\right)=6L(x)=6
L(x)=3L\left(x\right)=3L(x)=3
L(x)=9L\left(x\right)=9L(x)=9
undefined
L(x)=−6L\left(x\right)=-6L(x)=−6
L(x)=5L\left(x\right)=5L(x)=5
Determine the linear approximation of f(x)=5x^3+6 at a=0.
Determine the linear approximation of at a=0.
L(x)=2L\left(x\right)=2L(x)=2
L(x)=4L\left(x\right)=4L(x)=4
Determine the linear approximation of at a=0a=0a=0 .
L(x)=0L\left(x\right)=0L(x)=0
L(x)=1L\left(x\right)=1L(x)=1
L(x)=−3L\left(x\right)=-3L(x)=−3
L(x)=−2L\left(x\right)=-2L(x)=−2
L(x)=−1L\left(x\right)=-1L(x)=−1
L(x)=−3+xL\left(x\right)=-3+xL(x)=−3+x
L(x)=3+xL\left(x\right)=3+xL(x)=3+x
It is done.