1 / 10
00
What is the equation of the line tangent to
y=48x−65y=48x-65y=48x−65
y=0y=0y=0
y=−5x+1y=-5x+1y=−5x+1
y=−1y=-1y=−1
y=−10x−6y=-10x-6y=−10x−6
y=8x−7y=8x-7y=8x−7
y=3x+5y=3x+5y=3x+5
y=−3y=-3y=−3
y=3x−29y=3x-29y=3x−29
It is done.