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Select the graph of hyperbola (x−3)29−y249=1\frac{\left(x-3\right)^2}{9}-\frac{y^2}{49}=19(x−3)2−49y2=1
Select the graph of hyperbola x216−(y+2)249=1\frac{x^2}{16}-\frac{\left(y+2\right)^2}{49}=116x2−49(y+2)2=1
Select the graph of hyperbola x216−y24=1\frac{x^2}{16}-\frac{y^2}{4}=116x2−4y2=1
Select the graph of hyperbola (x−3)29−y24=1\frac{\left(x-3\right)^2}{9}-\frac{y^2}{4}=19(x−3)2−4y2=1
Select the graph of hyperbola x216−(y+2)24=1\frac{x^2}{16}-\frac{\left(y+2^{ }\right)^2}{4}=116x2−4(y+2)2=1
Select the graph of hyperbola x29−y216=1\frac{x^2}{9}-\frac{y^2}{16}=19x2−16y2=1
Select the graph of hyperbola (x−3)29−y29=1\frac{\left(x-3\right)^2}{9}-\frac{y^2}{9}=19(x−3)2−9y2=1
Select the graph of hyperbola x264−(y+2)29=1\frac{x^2}{64}-\frac{\left(y+2\right)^2}{9}=164x2−9(y+2)2=1
Select the graph of hyperbola x216−y249=1\frac{x^2}{16}-\frac{y^2}{49}=116x2−49y2=1
Select the graph of hyperbola x29−y24=1\frac{x^2}{9}-\frac{y^2}{4}=19x2−4y2=1
It is done.