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Is the sentence true or false?
(1+x)/(2-x) does not exist due to unbounded behavior
True
False
If g(x) ={2, x<0 -3x, x ≥ 0}
Then g(x) does not exist due to unbounded behavior
(1+x)(2−x)\frac{\left(1+x\right)}{\left(2-x\right)}(2−x)(1+x) does not exist due to unbounded behavior
Evaluate
(1+x)(2−x)\frac{\left(1+x\right)}{\left(2-x\right)}(2−x)(1+x) =
-3
-2
fail to exist
31−x=\frac{3}{1-x}=1−x3=
1
2
x5x−5=\frac{x\sqrt{5}}{x-5}=x−5x5=
1x\frac{1}{x}x1 does not exist due to unbounded behaviour
(1+x)(4−x)\frac{\left(1+x\right)}{\left(4-x\right)}(4−x)(1+x) does not exist due to unbounded behavior
If g(x) ={-x-1, x<1 -3x, x ≥ 1}
(1+x)(1−x)\frac{\left(1+x\right)}{\left(1-x\right)}(1−x)(1+x) does not exist due to unbounded behaviour
It is done.