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What is the result of multiplying two complex numbers z1=5 cis(π/6) and z2=3 cis(π/6) in polar form?
15 cis(π/3)
8cis(π/3)
15cis(π/6)
What is the result of multiplying two complex numbers z1=3 cis(π/4) and z2=7cis(-π/6) in polar form?
21 cis (π/12)
21 cis (π/6)
21cis (π/4)
What is the result of multiplying two complex numbers z1=13 cis(π/2) and z2= cis(π/6) in polar form?
-13cis (2π/3)
13cis (2π/3)
13cis (-2π/3)
What is the result of multiplying two complex number z1=11 cis (π/2) and z2= cis (π/2) in polar form?
11 cis (π)
11 cis (π/2)
11cis (π/3)
What is the result of multiplying two complex numbers z1=4 cis(π/4) and z2=3 cis (π/4) in polar form?
12 cis (π/2)
12 cis (π/4)
7 cis (π/4)
What is the result of multiplying two complex numbers z1=r1 cis(θ1) and z2=r2 cis(θ2) in polar form?
r1r2cis (θ1+ θ2)
(r1+r2) cis (θ1+ θ2)
When multiplying a complex number by its conjugate in polar form, what happens to the argument (angle) of the result?
It becomes zero
It remains the same
It becomes π/2
What is the result of multiplying two complex numbers z1=2 cis(π/2) and z2=7 cis(π/3) in polar form?
14 cis (5π/6)
14 cis (π/4)
When multiplying complex numbers in polar form, what happens to their magnitudes?
They are added
They are subtracted
They are multiplied
When multiplying complex numbers in polar form, what happens to their arguments (angles)?
It is done.