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What is the result of dividing two complex numbers z1 = r1 cis(θ1)and z2 = r2 cis(θ2) in polar form?
R1r2cis(θ1+ θ2)
(r1+r2) cis(θ1+ θ2)
R1/r2 cis(θ1- θ2)
If z1= 11cis(π/2) and z2= cis(π/6), what is the quotient of z1 and z2 in polar form?
11 cis(π/3)
Cis(π/3)
11cis(π/6)
When finding the reciprocal of a complex number z in polar form, what happens to the magnitude of the reciprocal of z?
It is added
It is subtracted
It is divided by magnitude of z
In polar form, if the reciprocal of a complex number has an argument (angle) of zero, what can you say about the angle of the original complex number?
It remains the same
It becomes zero
It becomes π
If z1= 6cis(π/3) and z2= 3cis(-π/4), what is the quotient of z1 and z2 in polar form?
-2 cis(7π/12)
cis(π/12)
2cis(7π/12)
When dividing complex numbers in polar form, what happens to their arguments (angles)?
They are added
They are subtracted
They are multiplied
When finding the reciprocal of a complex number in polar form, what happens to the argument (angle) of the reciprocal?
It is negative of magnitude of z
If z=3cis(π/4), what is the reciprocal of z in polar form?
Cis(-π/4)/3
Cis(π/4)/3
-Cis(-π/4)/3
What happens to the magnitude of the reciprocal of a complex number when the argument of the original complex number is π/2 in polar form?
The magnitude is added.
The magnitude is multiplied.
The magnitude of the reciprocal remains the same.
If z1= 5cis(π/2) and z2= 4cis(π/4), what is the quotient of z1 and z2 in polar form?
(5/4) cis(π/4)
(5/4) cis(-π/4)
(-5/4) cis(π/4)
It is done.