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In triangle ABC angle B = 40 degrees, angle C= 60 degrees and side a=7 units. What is the length of side c using the Law of Sines?"
5.5
9.4
6.15
7.9
Is the sentence true or false?
Law of sine can also be written as sin(A)a=sin(B)b=sin(C)c\frac{\sin\left(A\right)}{a}=\frac{\sin\left(B\right)}{b}=\frac{\sin\left(C\right)}{c}asin(A)=bsin(B)=csin(C)
True
False
In ASA-oblique triangle the ratio of the length of a side to the sine of the angle opposite that side is a constant value.
Fill in the blank:
In Law of Sines to solve oblique triangle (ASA), the sum of two given angle should be ______.
Equal to third angle
Right angle
Squair of third angle
None
Law of sine to solve ASA triangle a/c =
(a/c)= sinsin(A)×sinsin(C)
(a/c)= sinsin(A)/sinsin(C)
(a/c)= sinsin(A) +or - sinsin(C)
(a/c)= sinsin(A)sinsin(C)
To use the Law of Sines to solve oblique triangle (ASA), two angles and ______ of the triangle should be known.
a) two adjacent sides
a non-included side
side between the given angles
none
In Law of Sines to solve oblique triangle (ASA), reaming two sides are always equal
In oblique triangle when two angles and a side between these angles is known, then______ law is used.
Law of sine
Law of cosine
Lae of tangent
Identity law
In oblique triangle if angles A, B and side c is given then the length of side c is given by:
a=bsinsin(B)a=\frac{b}{\sin\sin\left(B\right)}a=sinsin(B)b
a=c(sin(A))sin(C)a=\frac{c\left(\sin\left(A\right)\right)}{\sin\left(C\right)}a=sin(C)c(sin(A))
a=b(sinsin(C))sin(B)a=\frac{b\left(\sin\sin\left(C\right)\right)}{\sin\left(B\right)}a=sin(B)b(sinsin(C))
a=bsin(B)sin(A)a=\frac{b\sin\left(B\right)}{\sin\left(A\right)}a=sin(A)bsin(B)
In law of sine(c×sin(A))/(sin(C)×a)=
Sin(B)
1/sin(B)
1
It is done.