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Questions

1 / 10

Time

Score

Solving systems of linear equations by substitution method

Solve for the ordinate of the solution of $x+y=2$ and $x-y=1$ using substitution.

$\frac{1}{2}$

0 $\frac{1}{3}$

Solve for the ordinate of the solution of $2x-3y=4$ and $x-2y=1$ using elimination method.

0

1

2

Solve for the abscissa of the solution of $x+2y=4$ and $x+y=1$ using substitution method.

-2

2

0

Solve for the abscissa of the solution of $x+2y=4$ and $x-y=1$ using elimination method.

2

1

3

Solve for the abscissa of the solution of $x+y=2$ and $x-y=1$ using substitution method.

$\frac{3}{2}$

$11$

0

Solve for the ordinate of the solution of $x+2y=4$ and $x-y=1$ using elimination method.

0

1

8

Solve for the ordinate of the solution of $2x+y=1$ and $x+y=1$ using substituition method.

-2

1

3

Solve for the ordinate of the solution of $x+2y=4$ and $x+y=1$ using elimination method.

-3

3

2

Solve for the abscissa of the solution of $2x-3y=4$ and $x-2y=1$ using elimination method.

5

2

0

Solve for the abscissa of the solution of $2x+y=1$ and $x+y=1$ using substituition method.

0

1

2

Questions

Time

Score

Solving systems of linear equations by substitution method

Solve for the ordinate of the solution of ﻿x+y=2x+y=2x+y=2﻿ and ﻿x−y=1x-y=1x−y=1﻿ using substitution.

﻿12\frac{1}{2}21​﻿

0

﻿13\frac{1}{3}31​﻿

Solve for the ordinate of the solution of ﻿2x−3y=42x-3y=42x−3y=4﻿ and ﻿x−2y=1x-2y=1x−2y=1﻿ using elimination method.

0

1

2

Solve for the abscissa of the solution of ﻿x+2y=4x+2y=4x+2y=4﻿ and ﻿x+y=1x+y=1x+y=1﻿ using substitution method.

-2

2

0

Solve for the abscissa of the solution of ﻿x+2y=4x+2y=4x+2y=4﻿ and ﻿x−y=1x-y=1x−y=1﻿ using elimination method.

2

1

3

Solve for the abscissa of the solution of﻿x+y=2x+y=2x+y=2﻿ and ﻿x−y=1x-y=1x−y=1﻿ using substitution method.

﻿32\frac{3}{2}23​﻿

﻿111111﻿

0

Solve for the ordinate of the solution of ﻿x+2y=4x+2y=4x+2y=4﻿ and ﻿x−y=1x-y=1x−y=1﻿ using elimination method.

0

1

8

Solve for the ordinate of the solution of ﻿2x+y=12x+y=12x+y=1﻿ and ﻿x+y=1x+y=1x+y=1﻿ using substituition method.

-2

1

3

Solve for the ordinate of the solution of ﻿x+2y=4x+2y=4x+2y=4﻿ and ﻿x+y=1x+y=1x+y=1﻿ using elimination method.

-3

3

2

Solve for the abscissa of the solution of ﻿2x−3y=42x-3y=42x−3y=4﻿ and ﻿x−2y=1x-2y=1x−2y=1﻿ using elimination method.

5

2

0

Solve for the abscissa of the solution of ﻿2x+y=12x+y=12x+y=1﻿ and ﻿x+y=1x+y=1x+y=1﻿ using substituition method.

0

1

2

Incorrect

Great!

Solve for the ordinate of the solution of $x+y=2$ and $x-y=1$ using substitution.

$\frac{1}{2}$

$\frac{1}{3}$

Solve for the ordinate of the solution of $2x-3y=4$ and $x-2y=1$ using elimination method.

Solve for the abscissa of the solution of $x+2y=4$ and $x+y=1$ using substitution method.

Solve for the abscissa of the solution of $x+2y=4$ and $x-y=1$ using elimination method.

Solve for the abscissa of the solution of $x+y=2$ and $x-y=1$ using substitution method.

$\frac{3}{2}$

$11$

Solve for the ordinate of the solution of $x+2y=4$ and $x-y=1$ using elimination method.

Solve for the ordinate of the solution of $2x+y=1$ and $x+y=1$ using substituition method.

Solve for the ordinate of the solution of $x+2y=4$ and $x+y=1$ using elimination method.

Solve for the abscissa of the solution of $2x-3y=4$ and $x-2y=1$ using elimination method.

Solve for the abscissa of the solution of $2x+y=1$ and $x+y=1$ using substituition method.