$\left(\frac{1}{s}\right)'\left(x\right)=\frac{1}{3x}$

$\left(\frac{1}{s}\right)'\left(x\right)=\frac{1}{2x}$

$\left(\frac{1}{s}\right)'\left(x\right)=\frac{1}{x}$

$\left(\frac{1}{r}\right)'\left(x\right)=-\frac{3}{x^4}$

$\left(\frac{1}{r}\right)'\left(x\right)=\frac{3}{x^4}$

$\left(\frac{1}{r}\right)'\left(x\right)=\frac{3}{x^{ }}$

$\left(\frac{1}{g}\right)'\ \left(x\right)\ =\ \frac{1\ }{2\sqrt{x}}$

$\left(\frac{1}{g}\right)'\ \left(x\right)\ =\ -\frac{1}{2\sqrt{x}}$

$\left(\frac{1}{g}\right)'\ \left(x\right)\ =\ -2\sqrt{x}$

$\left(\frac{1}{v}\right)'\left(x\right)=-\frac{\cos^2x}{\tan^2x}$

$\left(\frac{1}{v}\right)'\left(x\right)=-2\frac{\cos^2x}{\tan^2x}$

$\left(\frac{1}{v}\right)'\left(x\right)=-3\frac{\cos^2x}{\tan^2x}$

$\left(\frac{1}{t}\right)'\left(x\right)=\frac{\sin x}{\cos^2x}$

$\left(\frac{1}{t}\right)'\left(x\right)=\frac{\sin x}{\cos^{ }x}$

$\left(\frac{1}{t}\right)'\left(x\right)=\frac{2\sin x}{\cos x}$

$\left(\frac{1}{w}\right)'\left(x\right)=-\frac{2}{x^3}$

$\left(\frac{1}{w}\right)'\left(x\right)=\frac{2}{x^3}$

$\left(\frac{1}{w}\right)'\left(x\right)=\frac{2}{x^{ }}$

$\left(\frac{1}{h}\right)'\left(x\right)=e^{-x}$

$\left(\frac{1}{h}\right)'\left(x\right)=e^x$

$\left(\frac{1}{h}\right)'\left(x\right)=e^{ }$

$\left(\frac{1}{m}\right)'\left(x\right)=\frac{\cos x}{\sin^2x}$

$\left(\frac{1}{m}\right)'\left(x\right)=\frac{-\cos x}{\sin^2x}$

$\left(\frac{1}{m}\right)'\left(x\right)=\frac{\cos x}{\sin^{ }x}$

$\left(\frac{1}{u}\right)'\left(x\right)=e^x$

$\left(\frac{1}{u}\right)'\left(x\right)=e^{-x}$

$\left(\frac{1}{u}\right)'\left(x\right)=2e^x$

$\left(\frac{1}{q}\right)'\left(x\right)=\frac{1}{x^2}$

$\left(\frac{1}{q}\right)'\left(x\right)=\frac{1}{x^{ }}$

$\left(\frac{1}{q}\right)'\left(x\right)=\frac{1}{2x^2}$