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The radius of a sphere is 1. Find volume of sphere?
v(x)=36πv(x)=36\piv(x)=36π
v(x)=43πv(x)=\frac{4}{3}\piv(x)=34π
The radius of a sphere is 3\sqrt{3}3 . Find volume of sphere?
v(x)=4π3v(x)=4\pi\sqrt{3}v(x)=4π3
v(x)=43π3v(x)=\frac{4}{3}\pi\sqrt{3}v(x)=34π3
A box without cover is to be constructed from a rectangular cardboard, measuring 6 cm by 10 cm by cutting out four square corners of length x cm.Let V represent the volume of the box. Find volume V of the for x=2.
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The radius of a sphere is 3. Find volume of sphere?
A box without cover is to be constructed from a rectangular cardboard, measuring 9 cm by 7 cm by cutting out four square corners of length x cm.Let V represent the volume of the box. Find the volume V of the box if x=3
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Write cubic function to solve given problems:
The length of a side of cube is 3. Find volume of cube ?
3
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The length of a side of cube is x. Find volume of cube if x=3.
v(x)=27v(x)=27v(x)=27
v(x)=9v(x)=9v(x)=9
A box without cover is to be constructed from a rectangular cardboard, measuring 4 cm by 2 cm by cutting out four square corners of length x cm.Let V represent the volume of the box. Find the volume V of the box if x=1.
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Consider a situation in which a rectangular piece of cardboard is folded into a box. The folding is made possible by cutting squares out of the four corners of the cardboard. The maximum volume possible of a box made from a sheet of cardboard 16" x 10" is v(x)=(16−x)(10−2x)xv(x)=(16−x)(10−2x)xv(x)=(16−x)(10−2x)x . Find volume if x=4
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Consider a situation in which a rectangular piece of cardboard is folded into a box. The folding is made possible by cutting squares out of the four corners of the cardboard. The maximum volume possible of a box made from a sheet of cardboard 6" x 4"is v(x)=(6−x)(4−2x)xv(x)=(6−x)(4−2x)xv(x)=(6−x)(4−2x)x . Find volume if x=2.
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It is done.