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A ladder placed against a wall such that it reaches the top of the wall of height 15 m and the ladder is inclined at an angle of 60°. Find how far the ladder is from the foot of the wall.
tan(60)=15base\tan\left(60\right)=\frac{15}{base}tan(60)=base15
tan(60)=6base\tan\left(60\right)=\frac{6}{base}tan(60)=base6
tan(60)=1250\tan\left(60\right)=\frac{12}{50}tan(60)=5012
A kite is flying with the inclination of the string with the ground is 60°. Find the height of the kite, if horizontal distance is 25 meters.
tan(60)=h25\tan\left(60\right)=\frac{h}{25}tan(60)=25h
tan(60)=h50\tan\left(60\right)=\frac{h}{50}tan(60)=50h
From the top of the tower 70 m height a man is observing the base of a tree at an angle of depression measuring 30°. Find the distance between the tree and the tower.
tan(30)=30d\tan\left(30\right)=\frac{30}{d}tan(30)=d30
tan(60)=60d\tan\left(60\right)=\frac{60}{d}tan(60)=d60
tan(30)=70d\tan\left(30\right)=\frac{70}{d}tan(30)=d70
A string of a kite is 100 meters long and the inclination of the string with the ground is 60°. Find the height of the kite, if horizontal distance is 50 meters.
tan(30)=h6\tan\left(30\right)=\frac{h}{6}tan(30)=6h
A toy ladder is set against a 10mm tall stack of coins. If the base of the ladder is 6mm away from the base of the coins, what angle of elevation does the ladder form?
tan(E)=186\tan\left(E\right)=\frac{18}{6}tan(E)=618
tan(E)=1822\tan\left(E\right)=\frac{18}{22}tan(E)=2218
tan(E)=106\tan\left(E\right)=\frac{10}{6}tan(E)=610
A toy ladder is set against a 18mm tall stack of coins. If the base of the ladder is 6mm away from the base of the coins, what angle of elevation does the ladder form?
tan(E)=18/6
tan(E)=18/22
tan(E)=22/68
The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.
tan(30)=h50\tan\left(30\right)=\frac{h}{50}tan(30)=50h
A ladder placed against a wall such that it reaches the top of the wall of height 6 m and the ladder is inclined at an angle of 60°. Find how far the ladder is from the foot of the wall.
From the top of the tower 30 m height a man is observing the base of a tree at an angle of depression measuring 30°. Find the distance between the tree and the tower.
tan(60)=30d\tan\left(60\right)=\frac{30}{d}tan(60)=d30
The angle of elevation of the top of the building at a distance of 70 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.
tan(60)=h70\tan\left(60\right)=\frac{h}{70}tan(60)=70h
It is done.