|BSM

Questions

1 / 10

Time

Score

Write Tangent Functions To Solve Word Problems

A kite is flying with the inclination of the string with the ground is 60°. Find the height of the kite, if horizontal distance is 25 meters.

$\tan\left(60\right)=\frac{h}{25}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{h}{50}$

A toy ladder is set against a 10mm tall stack of coins. If the base of the ladder is 6mm away from the base of the coins, what angle of elevation does the ladder form?

$\tan\left(E\right)=\frac{18}{6}$

$\tan\left(E\right)=\frac{18}{22}$

$\tan\left(E\right)=\frac{10}{6}$

A ladder placed against a wall such that it reaches the top of the wall of height 6 m and the ladder is inclined at an angle of 60°. Find how far the ladder is from the foot of the wall.

$\tan\left(30\right)=\frac{h}{6}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{12}{50}$

The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.

$\tan\left(30\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{12}{50}$

From the top of the tower 30 m height a man is observing the base of a tree at an angle of depression measuring 30°. Find the distance between the tree and the tower.

$\tan\left(30\right)=\frac{30}{d}$

$\tan\left(60\right)=\frac{60}{d}$

$\tan\left(60\right)=\frac{30}{d}$

A toy ladder is set against a 18mm tall stack of coins. If the base of the ladder is 6mm away from the base of the coins, what angle of elevation does the ladder form?

tan(E)=18/6

tan(E)=18/22

tan(E)=22/68

A string of a kite is 100 meters long and the inclination of the string with the ground is 60°. Find the height of the kite, if horizontal distance is 50 meters.

$\tan\left(30\right)=\frac{h}{6}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{h}{50}$

A ladder placed against a wall such that it reaches the top of the wall of height 15 m and the ladder is inclined at an angle of 60°. Find how far the ladder is from the foot of the wall.

$\tan\left(60\right)=\frac{15}{base}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{12}{50}$

From the top of the tower 70 m height a man is observing the base of a tree at an angle of depression measuring 30°. Find the distance between the tree and the tower.

$\tan\left(30\right)=\frac{30}{d}$

$\tan\left(60\right)=\frac{60}{d}$

$\tan\left(30\right)=\frac{70}{d}$

The angle of elevation of the top of the building at a distance of 70 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.

$\tan\left(30\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{h}{70}$

Questions

Time

Score

Write Tangent Functions To Solve Word Problems

A kite is flying with the inclination of the string with the ground is 60°. Find the height of the kite, if horizontal distance is 25 meters.

﻿tan⁡(60)=h25\tan\left(60\right)=\frac{h}{25}tan(60)=25h​﻿

﻿tan⁡(60)=6base\tan\left(60\right)=\frac{6}{base}tan(60)=base6​﻿

﻿tan⁡(60)=h50\tan\left(60\right)=\frac{h}{50}tan(60)=50h​﻿

A toy ladder is set against a 10mm tall stack of coins. If the base of the ladder is 6mm away from the base of the coins, what angle of elevation does the ladder form?

﻿tan⁡(E)=186\tan\left(E\right)=\frac{18}{6}tan(E)=618​﻿

﻿tan⁡(E)=1822\tan\left(E\right)=\frac{18}{22}tan(E)=2218​﻿

﻿tan⁡(E)=106\tan\left(E\right)=\frac{10}{6}tan(E)=610​﻿

A ladder placed against a wall such that it reaches the top of the wall of height 6 m and the ladder is inclined at an angle of 60°. Find how far the ladder is from the foot of the wall.

﻿tan⁡(30)=h6\tan\left(30\right)=\frac{h}{6}tan(30)=6h​﻿

﻿tan⁡(60)=6base\tan\left(60\right)=\frac{6}{base}tan(60)=base6​﻿

﻿tan⁡(60)=1250\tan\left(60\right)=\frac{12}{50}tan(60)=5012​﻿

The angle of elevation of the top of the building at a distance of 50 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.

﻿tan⁡(30)=h50\tan\left(30\right)=\frac{h}{50}tan(30)=50h​﻿

﻿tan⁡(60)=h50\tan\left(60\right)=\frac{h}{50}tan(60)=50h​﻿

﻿tan⁡(60)=1250\tan\left(60\right)=\frac{12}{50}tan(60)=5012​﻿

From the top of the tower 30 m height a man is observing the base of a tree at an angle of depression measuring 30°. Find the distance between the tree and the tower.

﻿tan⁡(30)=30d\tan\left(30\right)=\frac{30}{d}tan(30)=d30​﻿

﻿tan⁡(60)=60d\tan\left(60\right)=\frac{60}{d}tan(60)=d60​﻿

﻿tan⁡(60)=30d\tan\left(60\right)=\frac{30}{d}tan(60)=d30​﻿

A toy ladder is set against a 18mm tall stack of coins. If the base of the ladder is 6mm away from the base of the coins, what angle of elevation does the ladder form?

tan(E)=18/6

tan(E)=18/22

tan(E)=22/68

A string of a kite is 100 meters long and the inclination of the string with the ground is 60°. Find the height of the kite, if horizontal distance is 50 meters.

﻿tan⁡(30)=h6\tan\left(30\right)=\frac{h}{6}tan(30)=6h​﻿

﻿tan⁡(60)=6base\tan\left(60\right)=\frac{6}{base}tan(60)=base6​﻿

﻿tan⁡(60)=h50\tan\left(60\right)=\frac{h}{50}tan(60)=50h​﻿

A ladder placed against a wall such that it reaches the top of the wall of height 15 m and the ladder is inclined at an angle of 60°. Find how far the ladder is from the foot of the wall.

﻿tan⁡(60)=15base\tan\left(60\right)=\frac{15}{base}tan(60)=base15​﻿

﻿tan⁡(60)=6base\tan\left(60\right)=\frac{6}{base}tan(60)=base6​﻿

﻿tan⁡(60)=1250\tan\left(60\right)=\frac{12}{50}tan(60)=5012​﻿

From the top of the tower 70 m height a man is observing the base of a tree at an angle of depression measuring 30°. Find the distance between the tree and the tower.

﻿tan⁡(30)=30d\tan\left(30\right)=\frac{30}{d}tan(30)=d30​﻿

﻿tan⁡(60)=60d\tan\left(60\right)=\frac{60}{d}tan(60)=d60​﻿

﻿tan⁡(30)=70d\tan\left(30\right)=\frac{70}{d}tan(30)=d70​﻿

The angle of elevation of the top of the building at a distance of 70 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.

﻿tan⁡(30)=h50\tan\left(30\right)=\frac{h}{50}tan(30)=50h​﻿

﻿tan⁡(60)=h50\tan\left(60\right)=\frac{h}{50}tan(60)=50h​﻿

﻿tan⁡(60)=h70\tan\left(60\right)=\frac{h}{70}tan(60)=70h​﻿

Incorrect

Great!

$\tan\left(60\right)=\frac{h}{25}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{h}{50}$

$\tan\left(E\right)=\frac{18}{6}$

$\tan\left(E\right)=\frac{18}{22}$

$\tan\left(E\right)=\frac{10}{6}$

$\tan\left(30\right)=\frac{h}{6}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{12}{50}$

$\tan\left(30\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{12}{50}$

$\tan\left(30\right)=\frac{30}{d}$

$\tan\left(60\right)=\frac{60}{d}$

$\tan\left(60\right)=\frac{30}{d}$

$\tan\left(30\right)=\frac{h}{6}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{15}{base}$

$\tan\left(60\right)=\frac{6}{base}$

$\tan\left(60\right)=\frac{12}{50}$

$\tan\left(30\right)=\frac{30}{d}$

$\tan\left(60\right)=\frac{60}{d}$

$\tan\left(30\right)=\frac{70}{d}$

$\tan\left(30\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{h}{50}$

$\tan\left(60\right)=\frac{h}{70}$